-32x^2+180x=0

Solution for -32x^2+180x=0 equation:

-32x^2+180x=0

a = -32; b = 180; c = 0;
Δ = b2-4ac
Δ = 1802-4·(-32)·0
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-180}{2*-32}=\frac{-360}{-64}
=5+5/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+180}{2*-32}=\frac{0}{-64}
=0
$